HPHP48-R–*ðô   ex¨final.PR3,*0 "Problema 3:
*DATOS:
Nodo 1: G1 y G2[75KW,25KVAR]
Lin:120mi,r=.216,l=1.434m,.012\181
Nodo 2: C1:100KW,.9(-)
        C2:150KVA,30KVAR
        V:13.2KV 

*RESOLUCION:
-Nodo de Carga:
S2=Sc1+Sc2
S2=(100K+48.43Kj+146.97K+30Kj)/3
S2=86.374\12817.62K
I2=(S2/V2)\176
I2=(86.374\12817.62/(13.2K/\1313))\176
I2=11.33\128-17.62

-Linea:
Z=R+2\135fL*j
Z=.216*120+2\135*60*1.434E-3*120*j
Z=25.92+64.87*j
Y=G+2\135fC*j
Y=0+2\135*60*.012E-6*120*j
Y=5.43E-4*j
A=D=ZY/2
B=Z
C=Y*(1+YZ/4)
A=D=.982\128.410
B=69.86\12868.22
C=5.38E-4\12890.20
V1=A*V2+B*I2
I1=C*V2+D*I2
\134V1=8017\1284.76
I1=10.65\1284.34

-Nodo de Generacion:
Ig1=I1-(Sg2/V1)\176
Ig1=I1-((25K+25K/3*j)/V1)\176
\134Ig1=7.59\12812.04
Sg1=3*V1*I1\176=182.64\128-7.27KVA
\134Sg1=182.64KVA
\134Pg1=181.17KW
\134Qg1=-23.13KVAR
\134fp=.992(+)

-Otras Caracteristicas:
\148=Pout/Pin*100
\148=(100+146.97)/(75+181.17)*100
\134\148=96.41\037
\037REG=(\124V1\124/\124A\124-\124V2\124)*100/\124V2\124
\037REG=(8017/.982-V2)*100/V2
\134\037REG=7.12\037
Prmax=(\124V2\124\124V1\124-\124A\124\124V1\124^2*cos(\223-\140))/\124\223\124
\134Prmax=566.232KW"
	ÀP†‡j–æÆæ%%ÃÀ¢« %÷&ÆVÖ"£Ó  BDõ4¥Ó 0U&6–öæBVS—VRæF'W2öR× @VÂ62b6W6Â62VÆV6R6GæÖ 0öÖWW6G62öRBVB2&ÆV6BVÖ  ÄVW¦–B3Ãsc3’bƒ¤2WÖÒ  Fö6’WÇvF6‚ö&—¦÷æFÆ’× `W&G—6ÆÖVæFWæÒ Ð  ’äDU$õÄ4”ôä$"¥Ó  Ãsc3¤#ÕãƒcÓ À3CC3Ãsc3¤#Õã“##3ÃSsóÒ–ÆÆÖ PÃsc3¤#Õã“CÓ Ð  "U4õÄT5”ôä¤Ó @4÷%ö•æFÖÃ3Ã3ƒ"w¢Bæ5£Â3#“Òã2“csÓ @T×Ã3ƒSã%£2“Òƒã’Ó  wò•æFÖãCSÓ ÀÔãrCÃöv†ƒã’óâ2“cs“Ò–Æ–†ôÒ–ÆÆÖ ÀÔã"C3Ó†ôÒ–ÆÆÖ €Åöe6WÖ#£Â3S£b¦ÂÔ À3CƒÅöe6WÖCcƒã‚Ò–Æ–ÆSsóÒ–ÆÆöb6WÖ @47ÖÃ3Ã3ƒ"w¢Bæ5£Â3#“ÒãB#sÓ  wò5×ã"S“ó‚"£#“ÒãS#SÓ 0Ôã3ƒƒó‚Âöv†ƒã’óâB#c““’Ò 0Ô#ã2C“SÔ"ÂƒcôÒ–ÆÆÖ €5Öó‚"£3S£b¦2”Ò À3Cƒ5Ö#ã2s²ÄSsóÒ–ÆÆÖ  RÃsc3Ôã“C²ÇV–FöBVB&ÆÖ× À3C#Õã“CóBÓã#3S#SÂSsóÒ–ÆÆ&Ò À\ ex¨final.PR1,*°` "Problema 1:
*DATOS:
T1: 150MVA, 13.8/115KV, 10%
Linea: L=30millas,
       r=.0446, R=1.338
       x=.0893, X=2.679
T2: 150MVA, 115/13.2KV, 10%
C1: 15MVA, .9
C2: 45MVA, .9
Sb=100MVA
Vb=13.8KV

*TABLA:
Dato: Secc.I, Secc.II, Secc.III
Sb: 100M, 100M, 100M
Ib: 4183.7, 502.04, 4373.87
Vb: 13.8K, 115K, 13.2K
Zb: 1.904, 132.25, 1.744

*CIRCUITO EQUIVALENTE:
GND--[G]--[.0666j]-[.0101]-
[.0203j]-[.0666j]-{V=.9773}
-[C:S=.6,fp=.9]-GND

*RESOLUCION:
Ipu=(S/V)\176=.6139\128-25.84
Ig=Ipu*4183.7=2568.4\128-25.84A
\134Ig=2568.4A
\155V=Ipu*R=.0945\12860.396
Vgpu=\155V+.9773
Vgpu=1.027\1284.59
Vg=Vgpu*13.8K=14.17\1284.59KV
\134Vg=14.17KV
Spu=.6307\12830.43=Vpu*Ipu\176
S=Spu*100M
\134S=63.07MVA
\134P=54.4KW
\134Q=31.94KVAR
\134fp=.862(-)"